Determine the possible real value of n such that:
Arctan(1/3)+Arctan(1/4)+Arctan(1/5)+Arctan(1/n)= Arctan(1)
the sum of arctangent formula makes this a snap:
arctan(a)+arctan(b)=arctan((a+b)/(1-ab))
Rewrite the equation as
Arctan(1/3)+Arctan(1/4)+Arctan(1/5)-Arctan(1)= -Arctan(1/n)
then apply the formula 3 times
Arctan(7/11)+Arctan(1/5)-Arctan(1)= -Arctan(1/n)
Arctan(7/11)+Arctan(-2/3)= -Arctan(1/n)
Arctan(-1/47) = Arctan(-1/n)
n=47
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Posted by Jer
on 2024-04-26 08:51:44 |