The sum of the squares of four consecutive integers is two less than a square number.
What is the mean of the four integers?
(a) The mean of ((x+2)+(x-1)+x+(x+1))/4 = x+1/2
(b) The given equation:
Let (x+2)^2+(x-1)^2+x^2+(x+1)^2=y^2-2
Then 4(x^2+x+2) = y^2 or (2x+1)^2= y^2-7
Let a=(2x+1): a^2=y^2-7,
by inspection, a=+/-3, y==/-4
Then:
a=3, x=1, mean = 3/2
a=-3, x=-2, mean = -3/2
Edited on May 7, 2024, 10:52 am
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Posted by broll
on 2024-05-07 07:13:47 |