clc,clearvars
sides=[1,4,7,8];
s=sum(sides)/2
diffs=[s,s,s,s]-sides
K=sqrt(prod(diffs))
finds the largest such area, being that of this quadrilateral inscribed in a circle:
s =
10
diffs =
9 6 3 2
K =
18
where K is the desired area, which is the square root of the product of the four differences of the sides from half the sum of the sides.
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Posted by Charlie
on 2024-05-13 17:11:37 |