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Real Crossed Exponential Puzzle (Posted on 2024-05-18) Difficulty: 3 of 5
Determine all possible real numbers x, that satisfy this equation:

xx4 = 64

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

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Solution proposed solution | Comment 1 of 2
x^(x^4)=64

(x^4)*log(x)= log(64)

After narrowing down some:

for x=1.681792830:.0000000001:1.681792831
  fprintf('%11.9f %11.9f %11.9f\n',x,(x^4)*log(x),log(64))
end

1.681792830 4.158883076 4.158883083
1.681792830 4.158883077 4.158883083
1.681792830 4.158883079 4.158883083
1.681792830 4.158883080 4.158883083
1.681792830 4.158883082 4.158883083
1.681792831 4.158883083 4.158883083   <--------------
1.681792831 4.158883085 4.158883083
1.681792831 4.158883086 4.158883083
1.681792831 4.158883088 4.158883083
1.681792831 4.158883089 4.158883083
1.681792831 4.158883091 4.158883083

Wolfram Alpha identifies 1.681792831 as an approximation to 2^(3/4).

Graphing shows the LHS is monotonically increasing for positive numbers making this the only positive solution.

There are values that seem to meet the requirement around x = -0.515 and x = -0.591, but this is based on a graphing that shows only the real component of what is calculated to be a complex number, in each case.

  Posted by Charlie on 2024-05-18 21:32:34
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