All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Roots in modified fractions (Posted on 2024-05-19) Difficulty: 3 of 5
If x1,x2,x3 are the roots of equation x3-x-1=0 then compute

(2024+x1)/(2024-x1)+(2024+x2)/(2024-x2)+(2024+x3)/(2024-x3)

No Solution Yet Submitted by Danish Ahmed Khan    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts Puzzle Thoughts | Comment 2 of 3 |
The required value of the expression is:
24874411499/8291467799.

  Posted by K Sengupta on 2024-05-19 12:17:58
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information