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OOO3= one out of three (Posted on 2010-11-04) Difficulty: 4 of 5
Given an equation x^2+y^2+z^2=2010.
1. Prove that in every triplet of integers satisfying the above equation one number has to be even and two others odd.
2. How many integer solutions are there ?


Warning: 1 is very easy, 2 is quite tricky.

No Solution Yet Submitted by Ady TZIDON    
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re: Puzzle Answer Comment 10 of 10 |
(In reply to Puzzle Answer by K Sengupta)

If only positive integers are considered,  then there are precisely 8 non trivial triplets as follows: (1,28,35),   (4,25,37),  (5,7,44),   (5,31,32) , (7,19,40),  (11,17,40),   (16,23,35)  and (19,25,32).

Each of these can be permuted 6 ways, producing 48 positive integral solutions.

Each of x, y and z can, independently, be made positive or negative, multiplying the solutions by 2^3 = 8, making the final number of integer solutions 8*6*8 = 384.

Edited on June 3, 2024, 9:45 am
  Posted by K Sengupta on 2024-06-03 09:44:10

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