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Square-sum fraction (Posted on 2024-06-04) Difficulty: 2 of 5
If x2/y2 + y2/x2 = 254, then find the value of x5/y5 + y5/x5.

No Solution Yet Submitted by Danish Ahmed Khan    
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Solution computer solution | Comment 3 of 4 |
Treating x^2/y^2 as variable r, with x/y as its square root:


syms r
s=solve(r+1/r==254);
for i=1:2
  r=s(i)
  eval(r)
  eval(sqrt(r))
  eval(sqrt(r)^5+sqrt(1/r)^5)
  disp(' ')
end
       output                             annotation
r =
127 - 48*7^(1/2)                            x^2/y^2 
ans =
       0.00393706889964562                  evaluated
ans =
        0.0627460668061802                  x/y
ans =
          1028176.00000394                  (x/y)^5 + (y/x)^5
 
r =
48*7^(1/2) + 127                             x^2/y^2
ans =
            253.9960629311                   evaluated
ans =
          15.9372539331938                   x/y
ans =
                   1028176                   (x/y)^5 + (y/x)^5
 
 
answer: 1028176

and remaining symbolic

Completely symbolic version:

simplify(sqrt(r)^5+sqrt(1/r)^5)

gives the same answer, 1028176, without the eval().


  Posted by Charlie on 2024-06-05 06:04:18
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