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Recurrent Sequence Riddles (Posted on 2024-07-11) Difficulty: 3 of 5
The sequence an is defined by the recurrence relation an+4 = an+3 - an+2 + an+1 - an with initial values a0=1607, a1=1707, a2=1814 and a3=1914. Find a100.

No Solution Yet Submitted by Danish Ahmed Khan    
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Solution Solution | Comment 2 of 3 |
The sequence repeats with a cycle of 10, the first 10 elements are:
1607, 1707, 1814, 1914, 200, -1607, -1707, -1814, -1914, -200

So element 100 is the same as element 0 which is 1607

Consider labelling the elements of the sequence:  a,b,c,d,e,f,g,...
a is the 0-th element and k is the 10th.
Each element is the opposite of the one 5 places before.

e = d-c+b-a
f = (d-c+b-a) -d+c-b = -a
g = (-a) - (d-c+b-a) + d - c = -b
h = (-b) - (-a) + (d-c+b-a) - (d) = -c
i = (-c) - (-b) + (-a) - (d-c+b-a) = -d
j = (-d) - (-c) + (-b) - (-a) = -e
k = (-e) - (-d) + (-c) - (-b) = -f = a
etc

  Posted by Larry on 2024-07-11 11:13:52
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