All about
flooble
|
fun stuff
|
Get a free chatterbox
|
Free JavaScript
|
Avatars
perplexus
dot
info
Home
>
Just Math
Circle Search (
Posted on 2024-07-23
)
The points of intersection of the curves with equations 21y = 5x
2
+ 2x – 135 and 21y = (x – 5)(21x
2
+ 26x - 225) all lie on a circle C. Find the center and radius of C.
No Solution Yet
Submitted by
Danish Ahmed Khan
No Rating
Comments: (
Back to comment list
| You must be logged in to post comments.
)
Solution
| Comment 1 of 2
5x^2 + 2x – 135 = (x – 5)(21x^2 + 26x - 225)
(x - 5)(5x + 27) = (x – 5)(21x^2 + 26x - 225)
So (5,0) is one point of intersection
5x + 27 = 21x^2 + 26x - 225
21x^2 + 21x - 252 = 0
x^2 + x - 12 = 0
(x+4)(x-3) = 0
x values of intersection: {+5, -4, +3}
3 points of intersection (5,0) (-4,-3) (3,-4)
Center (0,0)
Radius 5
x^2 + y^2 = 25
https://www.desmos.com/calculator/ga9rktn32f
Posted by
Larry
on 2024-07-23 13:26:55
Please log in:
Login:
Password:
Remember me:
Sign up!
|
Forgot password
Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ
|
About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
blackjack
flooble's webmaster puzzle
Copyright © 2002 - 2024 by
Animus Pactum Consulting
. All rights reserved.
Privacy Information