perplexus.info :: Just Math : Given the Sum, Find the Sum

Given the Sum, Find the Sum (Posted on 2024-05-29)

Given that:

a+b+c= 2022

1/(a²⁰²²) + 1/(b²⁰²²) + 1/(c²⁰²²) = 1/2022
Find the value of:

1/(a²⁰²³) + 1/(b²⁰²³) + 1/(c²⁰²³)

**** Adapted from a problem appearing in Vietnamese IMO, 2022

See The Solution Submitted by K Sengupta

Rating: 5.0000 (1 votes)

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Question

Comment 2 of 2 |

The very first line of the official solution has

1/a+1/b+1/c=1/2022=1/(a+b+c)

Where does the first half of the equality come from?

Posted by Brian Smith on 2024-07-25 21:05:35

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