A ladder 20 ft long is leaning against a wall. Now, the bottom of the ladder is pushed horizontally away from the wall at a rate of 1.5 ft/sec.
How fast is the top of the ladder sliding down the wall when the bottom is 16 ft from the wall?
x^2 + y^2 = 400
y = √(400 - x^2)
dx/dt = 1.5 ft/sec (call it positive because x is increasing)
dy/dt = -(2x)(dx/dt) / 2√(400 - x^2)
dy/dt at x=16 is
-(16)(1.5) / √(400 - 256)
- 24 / √144 = -2 ft/sec
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Posted by Larry
on 2024-07-31 09:53:50 |