All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Sliding Ladder (Posted on 2024-07-31) Difficulty: 3 of 5
A ladder 20 ft long is leaning against a wall. Now, the bottom of the ladder is pushed horizontally away from the wall at a rate of 1.5 ft/sec.

How fast is the top of the ladder sliding down the wall when the bottom is 16 ft from the wall?

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution Comment 1 of 1
x^2 + y^2 = 400
y = √(400 - x^2)
dx/dt = 1.5 ft/sec   (call it positive because x is increasing)
dy/dt = -(2x)(dx/dt) / 2√(400 - x^2)
dy/dt at x=16 is
  -(16)(1.5) / √(400 - 256)
  - 24 / √144  = -2 ft/sec

  Posted by Larry on 2024-07-31 09:53:50
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (12)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information