KATHRYN and her school friends have been using a Lorenz-type code to pass covert messages to each other. Each letter is expressed as a five-digit binary number such that A = 1 = 00001, M = 13 = 01101 and so on, but other symbols are represented by 00000 and by 11011 upwards.
A fixed letter, say M, is chosen as a “coder”, known only to the sender and receiver. To transmit a letter, say D, it is added to the coder by the “exclusive-NOR” rule 1 + 1 = 1, 1 + 0 = 0, 0 + 1 = 0, 0 + 0 = 1. So, for example, D + M = 00100 + 01101 = 10110 = V. When the sent letter V is added by the recipient to the coder M, the original letter reappears: 10110 + 01101 = 00100.
She has sent her name to her friends as seven letters. KATHRYN and its coded version together consist of 14 different letters.
What was the coded version?
Note: Adapted from Enigma Number:1764 by Adrian Sommerfield, which appered in the New Scientist on 28 August, 2013.
Hello @
geometry dash lite,
To find the coded version of "KATHRYN," we need to use the given Lorenz-type code and the exclusive-NOR rule described in the puzzle.
Given Information:
A = 00001
M = 01101
Exclusive-NOR Rule: 1 + 1 = 1, 1 + 0 = 0, 0 + 1 = 0, 0 + 0 = 1
Let's break down the process step by step:
1. Convert each letter of "KATHRYN" to binary using the provided code:
K = 10 (Since K is not provided in the given information, we will use 10)
A = 00001
T = 10100
H = (Assume H = 10000)
R = (Assume R = 10001)
Y = (Assume Y = 10010)
N = 01110
2. Choose a fixed letter as the coder, which is M = 01101.
3. Add the binary representation of each letter to M using the exclusive-NOR rule:
K + M = 10 + 01101 = 01111
A + M = 00001 + 01101 = 01100
T + M = 10100 + 01101 = 11001
H + M = 10000 + 01101 = 11101
R + M = 10001 + 01101 = 11100
Y + M = 10010 + 01101 = 11111
N + M = 01110 + 01101 = 00011
4. The coded version of "KATHRYN" is the binary representation of these results:
Coded version = 01111 01100 11001 11101 11100 11111 00011
Therefore, the coded version of "KATHRYN" is 01111 01100 11001 11101 11100 11111 00011.