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Product of consecutive (Posted on 2024-09-11)

Find all integers n such that n⁴-8n+15 is product of two consecutive integers.

No Solution Yet Submitted by Danish Ahmed Khan

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some

| Comment 1 of 3

for n=1:9999

v=n^4-8*n+15;

div=divisors(v);

l=length(div)/2;

if l==round(l)

if div(l+1)-div(l)==1

disp([n v])

disp([div(l:l+1)])

disp(' ')

end

finds

     3    72   n and the value of the expression
     8     9   the two consecutive factors to make the expression
 
     5   600   n and the value of the expression
    24    25   the two consecutive factors to make the expression

Posted by Charlie on 2024-09-11 09:48:31

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