Father A is twice the age of the difference in years of the ages of Father B and Son A, who is one and a half times older than Son B.

Father B is currently twice the age of Son A is going to be when Son B will be double the age he is now.

All of the ages are multiples of five.

How old is Father A?

(In reply to Most realistic solution by Bryan)

Wording of the problem is a bit risky ... if Sa is 1.5 times OLDER than Sb, then he is actually Sa = 1.5Sb +Sb, in which case Sa is 25, and both fathers are 50. 1.5 times the age of is better. When you say 1.5 times older than, then the difference is what you are referring to. As I end my sentence in a preposition, which is acceptable these days, I'll just say, so what, right. This is just for fun.

Posted by Lawrence on 2003-08-24 14:29:44