Determine all possible real values of n that satisfy this equation:
nn = 81√6/32.
81 6^(1/2) / 32
= 3^4 3^(1/2) / [2^5 2^(-1/2) ]
= 3^(9/2) / 2^(9/2)
= 9^(9/4) / 4^(9/4) = (9/4) ^ (9/4) QED
(I was helped by knowing the answer)
Edited on October 2, 2024, 8:01 am