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Symmetric polynomial factorization (Posted on 2024-10-12)

Factorize the given polynomial

P(x)=(3x+2)(4x-3)(x-1)(12x+11)-14

No Solution Yet Submitted by Danish Ahmed Khan

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Solution

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P(x) = (3x+2) * (4x-3) * (x-1) * (12x+11) - 14

144*P(x) = 4*(3x+2) * 3*(4x-3) * 12*(x-1) * (12x+11) - 144*14

144*P(x) = (12x+8) * (12x-9) * (12x-12) * (12x+11) - 2016

144*P(x) = (144x^2-12x-72) * (144x^2-12x-132) - 2016

144*P(x) = (144x^2-12x-102+30) * (144x^2-12x-102-30) - 2016

144*P(x) = (144x^2-12x-102)^2 - 30^2 - 2016

144*P(x) = (144x^2-12x-102)^2 - 54^2

144*P(x) = (144x^2-12x-102+54) * (144x^2-12x-102-54)

144*P(x) = (144x^2-12x-48) * (144x^2-12x-156)

144*P(x) = 12*(12x^2-x-8) * 12*(12x^2-x-13)

P(x) = (12x^2-x-8) * (12x^2-x-13)

P(x) = (12x^2-x-8) * (12x-13) * (x+1)

Posted by Brian Smith on 2024-10-12 12:44:35

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