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Some Cubes Are 1 less than a Power of 3 (Posted on 2024-10-10)

Consider two positive integers x and y, and determine all possible pairs (x,y) that satisfy this equation:
x³ = 3^y - 1

Provide valid reasoning for your answer.

No Solution Yet Submitted by K Sengupta

Rating: 5.0000 (1 votes)

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Answer

Comment 2 of 2 |

x=2, y=2

2^3=8=9-1=3^2-1

Posted by Math Man on 2024-10-15 14:09:59

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