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Complex sequence (Posted on 2024-11-15) Difficulty: 3 of 5
Find n given that z = n ± √(-i) and

iz2=1 + 2/z + 3/z2 + 4/z3 + 5/z4 + ...

No Solution Yet Submitted by Danish Ahmed Khan    
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Solution Solution Comment 1 of 1
First lets start with a trick to simplify the right side.  Multiply the equation through by 1/z and then take the difference of the two equations.  That yields
iz^2 - iz = 1 + 1/z + 1/z^2 + 1/z^3 + 1/z^4 + ...

The right side is now a geometric series.  Then
iz^2 - iz = 1/(1 - 1/z)

Multiply both sides by 1/z and then simplify a bit to get
(z-1)^2 = -i

Then z = 1 +/- sqrt[-i], so n=1.

  Posted by Brian Smith on 2024-11-15 16:55:38
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