For all t in the interval 0≤t≤1, a thread is pinned from the point (0, t) on the y-axis to the corresponding point (1-t, 0) on the x-axis.
Under what curve do the threads lie?
(In reply to
Solution by Brian Smith)
If I am following your post correctly, in this section of your solution:
0 = t^2 + (x-y-1)*t - (y)
Then quadratic formula gets us
t = ((-x+y+1) +/- sqrt[(x-y-1)^2-4y]) / 2
Is it possible you have a sign error in the last line (-4y should be +4y)?
However, even with this change (if it is justified), this still is different from Larry's solution I believe.
Having said all this, I don't have the skills to offer my own solution. They only teach engineers enough math to understand formula derivations and solve the resulting problems. Other cool stuff that I have seen and learned from on this site was never on the table.
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Posted by Kenny M
on 2025-01-03 17:07:51 |
re: Solution
