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Logarithmic Quadratic Inquiry (Posted on 2025-01-06) Difficulty: 3 of 5
For what values of the constant c > 0 does the equation ln(x) = cx2 have solutions?

No Solution Yet Submitted by Danish Ahmed Khan    
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Solution Solution | Comment 1 of 3
From a graphical evaluation, there is a value of c between 0.18 and 0.19 where the 2 curves are tangent, and therefore have the same slope.  For smaller values of c, the two curves intersect below the x axis.

ln(x) = cx^2
take derivative of both sides
1/x = 2cx
1 = 2cx^2
1 = 2*ln(x)
ln(x) = 1/2
x = √e
ln(√e) = c(√e)^2
1/2 = ce
c = 1/(2e) = 0.1839397 approximately
- ∞ < c <= 1/(2e)

  Posted by Larry on 2025-01-06 10:28:15
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