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Maximizing Combined Quadrilateral Area (Posted on 2025-01-31) Difficulty: 3 of 5
Starting with a unit circle, draw two non-overlapping quadrilaterals inside. The vertices of the quadrilaterals may be on the circle, if you choose. They may also share vertices, edges, or partial edges, but their interiors may not overlap. They may be convex, concave, or one one of each, but may not be crossed.

What is the largest area these quadrilaterals combined can have?

No Solution Yet Submitted by Danish Ahmed Khan    
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soln (no proof) Comment 1 of 1
I suspect the best two quadrilaterals are each half a regular hexagon 
that fills the circle, sharing a diameter (i.e. two trapezoids). The 
reasoning is: the best use of perimeter to cover area is to 
approximate a circle as much as possible. The area is (3/2)sqrt(3) = 2.598 as opposed to the circle's area of pi. 

  Posted by Steven Lord on 2025-01-31 11:56:00
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