All about
flooble
|
fun stuff
|
Get a free chatterbox
|
Free JavaScript
|
Avatars
perplexus
dot
info
Home
>
Just Math
Extended Divisibility (
Posted on 2025-01-31
)
Let n and m be integer numbers. Prove that, if 3n+7m is divisible by 19, then the number 43n + 75m is divisible by 19 also.
No Solution Yet
Submitted by
Danish Ahmed Khan
Rating:
5.0000
(1 votes)
Comments: (
Back to comment list
| You must be logged in to post comments.
)
Answer
Comment 3 of 3 |
Suppose 19|3n+7m. Then, 19|8(3n+7m)=24n+56m. Since 19|19n+19m, then 19|(24n+56m)+(19n+19m)=43n+75m. Therefore, if 19|3n+7m, then 19|43n+75m.
Posted by
Math Man
on 2025-02-07 17:33:36
Please log in:
Login:
Password:
Remember me:
Sign up!
|
Forgot password
Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ
|
About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
blackjack
flooble's webmaster puzzle
Copyright © 2002 - 2025 by
Animus Pactum Consulting
. All rights reserved.
Privacy Information