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Log of Log equation (Posted on 2025-02-22) Difficulty: 3 of 5
Find the unique positive integer 𝑥 > 1 satisfying

log2log5x + log5log2x = log2(10/log25)

No Solution Yet Submitted by Danish Ahmed Khan    
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Solution Solution Comment 2 of 2 |
This is quite clearly a contest problem, meant to be solved by hand and not a computer.  Which also means there is likely some trick, or the right hand side is specially chosen to be solvable.

So lets just use log rules to manipulate the right side:
log2(10/log2(5))
= log2(2) + log2(5/log2(5))
= 1 + log2(5*log5(2))
= 1 + log2(log5(2^5))
= log5(5) + log2(log5(2^5))
= log5(log2(2^5)) + log2(log5(2^5))

Now the right side is in the same form as the left side.  The answer is now readily seen to be 2^5 = 32. 

  Posted by Brian Smith on 2025-02-22 18:02:11
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