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Nested Radical Product (Posted on 2025-03-05) Difficulty: 3 of 5
If

a = √(4 - √(5 - a))
b = √(4 + √(5 - b))
c = √(4 - √(5 + c))
d = √(4 + √(5 + d))

Determine the value of the product abcd.

No Solution Yet Submitted by Danish Ahmed Khan    
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Some Thoughts re(2): Iteration plus guess -- the iterative method | Comment 4 of 5 |
(In reply to re: Iteration plus guess -- the iterative method by Charlie)

Of course, I was just just being lazy.


What I find curious is that after the first iteration, the answer is exactly 11.  Then on the next iteration, the error is about .214, (not surprising), then eventually converges on:  11.000000000000004  rather than 11.

def fa(x):
    return (4 - (5 - x)**.5)**.5
def fb(x):
    return (4 + (5 - x)**.5)**.5
def fc(x):
    return (4 - (5 + x)**.5)**.5
def fd(x):
    return (4 + (5 + x)**.5)**.5

abcd = 0
a=b=c=d=0
delta = 100
while delta > 0:
    a = fa(a)
    b = fb(b)
    c = fc(c)
    d = fd(d)
    old = abcd
    abcd = a*b*c*d
    delta = abs(old - abcd)
    print(abcd)
print(abcd)
   
11.0
10.786239004264264
11.000095171765523
10.998597593440481
10.999984256915633
10.999989942052382
10.999999762932447
10.999999924707632
10.999999997400211
10.999999999421696
10.999999999974596
10.99999999999548
10.999999999999764
10.999999999999966
10.999999999999998
11.000000000000002
11.000000000000004
11.000000000000004
11.000000000000004

  Posted by Larry on 2025-03-06 07:25:18
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