If you square, rearrange, and square again, the first two equations take the form f(x)=x^4-8x^2+x+11 and the last two take the form
g(x)=x^4-8x^2-x+11.
a and b are roots of f(x) and c and d are roots of g(x). But f(-c)=g(c) so that -c is also a root of f(x), and likewise -d.
Then f(x)=(x-a)(x-b)(x+c)(x+d) with constant term abcd=11.
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Posted by xdog
on 2025-03-06 10:25:55 |