Find all positive numbers x such that
1 1 1
--- - ---- = ----
[x] [2x] 6{x}
where [x] represents the integer part of x and {x}=x-[x].
(In reply to
solution by Charlie)
[8/3] = 2
{8/3} = 2/3
Plugging 8/3 into the equation:
1 1 1
--- - ---- = ----
[x] [2x] 6{x}
1 1 1
--- - ---- = ----
2 5 4
|
Posted by Larry
on 2025-03-10 13:45:41 |