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Common root in quadratic combinations (Posted on 2025-03-08) Difficulty: 3 of 5
Let P(x) = x2 - 3x - 7, and let Q(x) and R(x) be two quadratic polynomials also with the coefficient of x2 equal to 1. David computes each of the three sums P + Q, P + R, and Q + R and is surprised to find that each pair of these sums has a common root, and these three common roots are distinct. If Q(0) = 2, then find R(0).

No Solution Yet Submitted by Danish Ahmed Khan    
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re: Thoughts | Comment 4 of 5 |
(In reply to Thoughts by Brian Smith)

Since I'm running through the math, I thought I would correct a few typos. The 2nd and 3rd lines here should read:


P+Q = 2*(x-a)*(x-b), P+R = 2*(x-a)*(x-c), and Q+R = 2*(x-b)*(x-c)
Then ((P+Q)+(P+R)-(Q+R))/2 = P makes P(x) = x^2 -2ax + (ab+ac-bc)

  Posted by Steven Lord on 2025-03-11 05:53:07
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