If:
2a = 3
3b = 4
4c = 5
5d = 6
Then, find the value of a*b*c*d
The stated problem requires logarithms at some point, but it can be done at the very end.
If 2^a=3 then raising both sides to the power b gives
2^(ab)=3^b=4
then
2^(abc)=5
2^(abcd)=6
So the answer is whatever number 2 must be raised to give 6/. Obviously a logarithm is needed at this point abcd = log2(6)
If we extend the problem (as in my other post) by defining
6^e=7
7^f=8
then
2^(abced)=7
2^(abcdef)=8
and so abcdef=3. No logs needed.
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Posted by Jer
on 2025-03-25 10:08:38 |
Logless solution
