If x, y>0 such that:
(x+y)(1/x+1/y)=5
Then, find the minimum value of:
(x
3+y
3)(1/x
3+1/y
3)
Rewrite the equation as (x+y)^2/xy=5.
The expression to be minimized can be rearranged and factored as (x^3+y^3)^2/(xy)^3=(x+y)^2*(x^2-xy+y^2)^2/(xy)^3.
Substitute the value from the equation and the expression becomes 5*(x^2-xy+y^2)^2/(xy)^2.
Write this as 5*((x+y)^2-3xy)/xy)^2
Divide each term by xy: 5*((x+y)^2/xy-3))^2
Substitute again: 5*(5-3)^2=5*4=20
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Posted by xdog
on 2025-03-28 14:14:02 |