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Given the product of linear expression, find the minimum (Posted on 2025-03-28) Difficulty: 3 of 5
If x, y>0 such that:
(x+y)(1/x+1/y)=5
Then, find the minimum value of:
(x3+y3)(1/x3+1/y3)

No Solution Yet Submitted by K Sengupta    
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different approach,same answer Comment 2 of 2 |
Rewrite the equation as (x+y)^2/xy=5.

The expression to be minimized can be rearranged and factored as (x^3+y^3)^2/(xy)^3=(x+y)^2*(x^2-xy+y^2)^2/(xy)^3.

Substitute the value from the equation and the expression becomes 5*(x^2-xy+y^2)^2/(xy)^2.

Write this as 5*((x+y)^2-3xy)/xy)^2

Divide each term by xy:  5*((x+y)^2/xy-3))^2

Substitute again:  5*(5-3)^2=5*4=20

  Posted by xdog on 2025-03-28 14:14:02
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