Find the function f(x), where:
f: R→R, and:
f(x+y)-f(x-y) = f(x)*f(y)
Let y = 0
Then f(x) - f(x) = f(x)*f(0)
so 0 = f(x)*f(0)
so f(0) = 0
Let y = x
then f(2x) - f(0) = f(x)*f(x)
so f(2x) = f(x)*f(x)
This implies that f(x) = a^x
But f(0) = 0, which seems like a contradiction.
The only function that I can figure out that works is f(x) = 0