Find the sum of the real values of x satisfying
2x2 + 20x + 21 2x2 + 24x + 11
-------------- = ---------------
2x2 − 12x + 20 2x2 − 8x + 10
Set A=2x^2+20x+21 and B=2x^2+24x+11.
Then the equation becomes A/(A-32x-1)=B/(B-32x-1).
Inverting gives (-32x-1)/A=(-32x-1)/B or A=B. So 4x=10 and x=5/2 is the sole solution.
|
Posted by xdog
on 2025-04-10 11:45:16 |