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Cube root infested denominator (Posted on 2025-04-12) Difficulty: 3 of 5
Simplify
      1              1              1
------------ + ------------ + --------------
∛1 + ∛2 + ∛4   ∛4 + ∛6 + ∛9   ∛9 + ∛12 + ∛16

No Solution Yet Submitted by Danish Ahmed Khan    
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Some thoughts? | Comment 1 of 3
The denominator of each term is of the form  (x*x)^(1/3) + (x*(x+1))^1/3 + ((x+1)*(x+1))^1/3  for x=1,2,3.   Not sure if this helps at all.
  Posted by Kenny M on 2025-04-13 06:06:06
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