One point:
If you center the circle at (pi,0) with radius pi it will contain (0,0).
(x-pi)^2+y^2=pi^2
I don't see how it can possibly contain any other rational points.
Two points:
You can make the circle contain (1,0) and (0,1) with radius pi and it center on the line y=x.
Center = (a,a) where a is either of the solutions to
a^2 + (a+1)^2 = pi. (Approximately -1.649 or 0.649)
Again, I don't see how this circle could possibly contain any other rational points.
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Posted by Jer
on 2025-04-14 09:14:22 |