Coins of diameter 1 have been placed in a square of side 11, without overlapping or protruding from the square. Can there be 126 coins? and 127? and 128?
Remove another row of 10 and replace with 11.
https://www.desmos.com/calculator/boogsxm4iw
There isn't room to do this one more time. If a greater number of circles than than 128 is possible, it will require another trick. There are still 4 offset rows, which can fit 8 half-circles. It's possible that with some jiggling, we can do even better.
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Posted by Jer
on 2025-04-23 08:24:33 |