Define:
d/dx(f(x)) = f'(x)
where f'(x) = gradient (or slope) of f(x) at x = x.
Prove that:
d/dx(x^2) = 2x
without using calculus.
(In reply to
re: Dumb question by Cheradenine)
Wow... that explains a lot of things. You're really asking for a calculus-less proof that the slope of
y = x²
is always going to be 2x for any given x. It's the damn "gradient" term that threw me off. Never heard "slope" referred to as such.
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Posted by levik
on 2002-08-01 05:28:24 |