If x, y and z are real numbers such that: x + y + z = 5 and xy + yz + zx = 3, what is the largest value that x can have ?
Well, I'm first noting that x is maximized when either y or z is 0. It doesn't matter which one is 0 due to the structure of the equations as they both lead to the same two variable equations with interchangable y and z. Solving these two two-variable equations yields an answer of x maximized at x = 5-√2 = 3.5857
This might make sense or I could just be talking out of my butt....
|
Posted by DuCk
on 2003-11-17 13:48:03 |