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The Powers that Be (Posted on 2003-11-25) Difficulty: 4 of 5
Is it possible for two complex numbers to have a real exponentiation?

In other words, if x and y are complex (each have the form a+bi), show that x^y can have a real value, or prove that it is impossible.

Note: i is the imaginary value defined as the number that yields -1 when squared. a and b are any real numbers, but b is not 0.

See The Solution Submitted by DJ    
Rating: 4.4444 (9 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: solution | Comment 12 of 21 |
(In reply to solution by luminita)

Your solution is much better than mine because you avoid using the logarithm function. For your solution, we do have to believe e^(it)=cos(t)+i*sin(t) for real t and that the law of exponents (a^b)^c=a^(b*c) extends from the real numbers to the complex numbers (or, in other words, not very much). You have really scaled the problem down to essentials. Excellent!
  Posted by Richard on 2003-11-26 19:00:29

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