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Consecutive Numbers and Subset Choice (Posted on 2016-02-09) Difficulty: 3 of 5
M is the number of six-element subsets that can be chosen from the set of the first 15 positive integers so that at least three of the six numbers are consecutive.
Find M.

  Submitted by K Sengupta    
Rating: 4.0000 (2 votes)
Solution: (Hide)
The required value of M is 4310.

For an explanation, refer to the solution submitted by Steve Herman in this location.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
General Solution (from the first T numbers)Steve Herman2016-02-10 20:55:43
SolutionJust counting (spoiler)Steve Herman2016-02-10 19:49:00
Solutionpossible (?) solutionAdy TZIDON2016-02-09 21:27:48
found the error in method 2Charlie2016-02-09 16:29:47
Solutionon the other handCharlie2016-02-09 16:15:26
Some Thoughts2 computer solutions; the second is probably rightCharlie2016-02-09 16:06:19
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