perplexus.info :: Shapes : Hexagon Hinder 2

Hexagon Hinder 2 (Posted on 2016-05-06)

The hexagon PQRSTU is such that:

(1) All its vertices lie on a circle, and:
(2) PQ = RS = TU, and:
(3) the diagonals PS, QT, RU meet at a point.

N is the intersection of PS and RT

Find:

 RN/NT
---------
(PR/RT)²

Submitted by K Sengupta

Rating: 4.5000 (2 votes)

Solution: (Hide)

(RN/NT)/(PR/RT)2 = 1
For an explanation, refer to the solution submitted by Harry in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Solution	Harry	2016-05-08 15:31:37
Observation	Jer	2016-05-07 21:35:32

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