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Quadratic and Perfect Square Query II (Posted on 2016-05-21) Difficulty: 3 of 5
Determine all possible values of a positive integer N such that:
N2 + 72N is a perfect square.

  Submitted by K Sengupta    
Rating: 5.0000 (1 votes)
Solution: (Hide)
Required integer values for N are =3,9,24,49,75,128,289,
And the corresponding squares are: 15,27,48,77,105,160,323.

Explanation:
72N should have the form 2aN+a^2, with 0<a<36.
This leads to N=a^2/(72-2a)
This gives:

N     N^2+72N
3       15^2
9       27^2
24      48^2
49      77^2
75     105^2
128    160^2
289    323^2

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Possible solutionarmando2016-05-21 10:15:17
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