perplexus.info :: Numbers : Cube + Single Digit = Perfect Square

Cube + Single Digit = Perfect Square (Posted on 2024-01-21)

Which is the highest cube n^3 < 10⁸ that can be incremented by a single digit from 1 to 9 to yield a perfect square?

For example, 8 is a perfect cube. When incremented by 1 it becomes 81, which is a perfect square.

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

The required cube is 18821096, since
18821096 =266³, and:
188210961= 13719²
For an explanation, refer to the solution submitted by Larry in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Computer solution	Larry	2024-01-21 13:21:12
computer solution	Charlie	2024-01-21 12:39:47

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