perplexus.info :: Numbers : Powers of Digits 2

Powers of Digits 2 (Posted on 2024-05-02)

Let N be a positive integer with an even number of decimal digits, say abcd...yz.

For how many N does a^b + c^d + ... + y^z? equal zy...dcba, that is, N with its digits reversed? One example is N=52, since 5^2 = 25.

[If 00 occurs, take its value as 1. Do not include any solutions ending with 00.]

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

{10, 52, 64455910} is the entire solution set.
For an explanation, refer to the solution submitted by Larry in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
re: Guest	K Sengupta	2024-05-09 21:26:14
re: Guest	K Sengupta	2024-05-09 21:25:40
Guest	Anonymously	2024-05-09 10:52:22
Guest	Anonymously	2024-05-09 10:51:47
Computer solution	Larry	2024-05-02 13:12:34

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