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The Conversing Club (Posted on 2003-12-29)

There are 10 tables in the Conversing Club and 15 members. Each day, 3 people sit together around each of 5 of 10 possible tables in the club talking to each other.

Every week (7 days) everyone is at the same table with everyone else exactly once. Also, nobody is at the same table twice in the course of a week to provide a change of scenery each time. The first day is as following:

ABC DEF GHI JKL MNO

(The second day A couldn't sit with B, or C; B couldn't sit with C; D couldn't sit with E or F, but could sit with A, B, or C.)

How could their schedule be configured?

(Based on Fifteen Schoolgirls)

Submitted by Gamer

Rating: 3.0000 (1 votes)

Solution: (Hide)

The schedule shown to me was as follows:

1: ABC DEF GHI JKL MNO 2: ADG BKN COL JKI MHF 3: AJM BEH CFI DKO GNL 4: AEK CGM BOI DHL JNF 5: AHN CDJ BFL GEO MKI 6: AFO BGJ CKH DNI MEL 7: AIL BDM CEN GKF JHO The table schedule as follows: (First group to fifth group)

1 2 3 4 5 8 6 7 9 10 3 5 4 1 2 7 6 8 9 1 4 5 3 10 2 6 7 8 10 1 5 4 3 9 2

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
This is how I solved it.	Penny	2003-12-30 13:26:36
re(2): solution--computer used	Charlie	2003-12-30 11:30:23
re: solution--computer used	Charlie	2003-12-30 11:03:34
solution--computer used	Charlie	2003-12-30 10:56:46
re: Solution (no computer program used)	Charlie	2003-12-30 10:22:35
Solution (no computer program used)	Penny	2003-12-30 04:54:21

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