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Shortest distance (Posted on 2003-12-10) |
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What is the shortest distance between two opposite points (two vertices separated by 2R) in the surface of a regular icosahedron? The regular icosahedron's edges are 1ft in length.
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Submitted by Antonio
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Rating: 4.0000 (2 votes)
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Solution:
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(Hide)
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Solution:
shortest distance = 7^(1/2)*1ft = 2.64575131106ft |
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