3. This was posed by the indian mathematician Ramanujan. Let's prove, using induction, that m+1= S(m)= 1√(1+m√(1+(m+1)√(1+...))). Obviously, for m=0, S(0)=1. We can write m+1=1√(1+mS(m+1)) and squaring gets m²+2m+1=1+mS(m+1) that agrees with S(m+1)=m+2.
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