perplexus.info :: Numbers : Sweet Sixteener

Sweet Sixteener (Posted on 2005-02-03)

For this problem, only positive whole numbers are to be considered. What is the smallest number that has exactly 16 numbers (including 1 and itself) that divide into it without remainder? Proof?

Submitted by Richard

Rating: 4.0000 (2 votes)

Solution: (Hide)

120 = 2*2*2*3*5. See Jer's posts for the story. (Note that by "proper divisor" Jer just means "positive divisor", whereas most people use the word "divisor" (unqualified) for any positive divisor of a number, reserving "proper divisor" for a (positive) divisor that is not the number itself.)

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Puzzle Answer	K Sengupta	2023-12-10 20:29:44
re(2): Solution -- wrong -- my dumb typo	Jer	2005-02-03 20:16:44
re: Solution -- wrong	Old Original Oskar!	2005-02-03 18:12:16
re: Answer	Penny	2005-02-03 17:23:49
Solution	Jer	2005-02-03 17:09:06
Answer	Old Original Oskar!	2005-02-03 15:03:24

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