5^(y-x)*(y+x) = 1 and (x+y)^(x-y) = 5
Substitute into the second yields 5^((x-y)^2) = 5 so (x-y)^2 = 1
Case 1: x-y=1 then x+y=5 solution: (3,2)
Case 2: x-y=-1 then x+y=1/5 solution: (-.4,.6)
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