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Polynomials (Posted on 2005-05-10) Difficulty: 3 of 5
For all x in the given ranges, polynomials f, g, and h satisfy the following equations:

|f(x)| + g(x) = 4x, x ≤ -2;
|f(x)| + g(x) = -2x², -2 < x ≤ 0;
|f(x)| + g(x) = h(x), x > 0;

What is the least possible value of f(10)?

  Submitted by Charlie    
Rating: 4.0000 (1 votes)
Solution: (Hide)
There is a break at x=-2 in the interaction of f and g, so f(x) must change sign at that point, going from positive to negative or vice versa.

Function f can reinforce or cancel out the quadratic and linear portions of g by the reversal of sign that takes place in the absolute value function, relative to the reversed sign of f at x=-2.

So g(x) must be 2x - x². To cancel in one area and reinforce in the other, f(x) must be either 2x + x² or -2x - x².

At x=10, the latter has the lower value, -120.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
AnswerK Sengupta2008-09-29 23:54:30
re(2): numerical answer, without explanationajosin2005-05-11 16:06:29
Solutionmay be the solution....suman2005-05-11 06:03:53
re: numerical answer, without explanationRichard2005-05-11 00:46:07
re: numerical answer, without explanationTristan2005-05-10 21:46:04
Some Thoughtsnumerical answer, without explanationJohn Reid2005-05-10 21:39:44
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