1. Create every possible two-digit combination. 2. Find their sum. 3. Sum the original three digits. 4. Divide your answer from part 2 by your answer to part 3.
What number do you always get, and why?
Call the original digits a, b, and c.
10a+b + 10b+a + 10a+c + 10c+a + 10b+c + 10c+b = 22a+22b+22c = 22(a+b+c) The digits, of course sum to a+b+c so dividing this gives 22.
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