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| Polynomial Divisions (Posted on 2007-08-13) |
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A polynomial P(x) is divisible by x-5. If P(x) is divided by x-2 then the quotient is polynomial Q(x) and the remainder is 30. What is the remainder when Q(x) is divided by x-5?
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Submitted by Brian Smith
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Rating: 3.2000 (5 votes)
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Solution:
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If P(x) divided by x-2 is has a quotient Q(x) and a remainder of 30, then P(x) = (x-2)*Q(x) + 30
Since polynomial P(x) is divisible by x-5, P(5) = 0
Then 0 = P(5) = (5-2)*Q(5) + 30 which simplifies to Q(5) = -10
That means the remainder of dividing Q(x) by x-5 is -10. |
Comments: (
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Subject |
Author |
Date |
 | Solution | K Sengupta | 2007-08-21 11:29:36 |
| Solution | Praneeth | 2007-08-13 07:48:36 |
| Solution | Old Original Oskar! | 2007-08-13 07:47:29 |
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